x^2+34x-576=0

Solution for x^2+34x-576=0 equation:

x^2+34x-576=0

a = 1; b = 34; c = -576;
Δ = b2-4ac
Δ = 342-4·1·(-576)
Δ = 3460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3460}=\sqrt{4*865}=\sqrt{4}*\sqrt{865}=2\sqrt{865}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-2\sqrt{865}}{2*1}=\frac{-34-2\sqrt{865}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+2\sqrt{865}}{2*1}=\frac{-34+2\sqrt{865}}{2}
$